An electric field E is applied between the plates a and b as shown in the figure a charge particle of mass m and charge q is projected along the direction as shown fig it's velocity v find vertical distance y covered by the partical when goes out of the electric field region

### Asked by arorarajaryan2003 | 28th Apr, 2021, 10:11: PM

Expert Answer:

### Force F acting on the charge q in electric field E is given as, F = ( qE )
Acceleration a experienced by charge, a = force / mass = (qE)/m ..........................(1)
Vertical displacement due to electric field, y = (1/2) a t^{2} ..................................(2)
where t is time of travel in electric field, t = distance / speed = x/v .........................(3)
Using eqn.(1) and eqn.(3) , we get vertical displacement y from eqn.(2) as
y = (1/2) [ (qE ) / m ] ( x / v )^{2 }

^{2}..................................(2)

^{2 }

### Answered by Thiyagarajan K | 29th Apr, 2021, 08:11: AM

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